Electrical Engineering

Graduated from YMCA University Uganda in 2018 I worked at some construction sites for 4 months Then i got a volunteer opportunity form UGVS

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AC Light switch using relay

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  There are alot of circuits on how to do this. Most of them require you to place the photosensor between the base (B) of the transistor and the Emitter (E). But i have found this method not to be working well so i decided to place the photosensor between the resistor and the power supply (DC). So how is this method different. First the photosensor is already sending power even at low lighting. So if the source is 12v, that means that power though the photosensor under low light is approximately 8v. This means that 8v won't be able to course an effect on the relay since the relay is 12v based. When a bright light is put in a close distance with the photosensor, There will be low resistance on the photosensor hence the desired power which will follow to the relay The point where I have labeled as " AC power out" is the off point at default on the relay. What I mean is that the point with AC power out is the one is not connected inside of  the relay at first. I have used a ...
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Mosfet and capacitor switch

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  In the usual circuits, the capacitor is not included in. So why did i add a capacitor. if u have ever built a touch switch using only a mosfet, u do know that when u touch on the off wires the mosfet will gain power over time and light up again. Which can be somewhat annoying. But when u add a capacitor as seen above. When u apply a plus or add the wires temporarily or use a push switch( this switch should not lock when pressed.), u charge the capacitor and when u release the capacitor still has charge hence it is still providing power and working as a line which joins both the gate(G) and the source(S) of the mosfet. REMEMBER; When u try to touch using this method it will not work coz the capacitor will need alot or current and voltage for it to charge at a small amount of time which ur fingers can't provide. So when u press the push switch on the gate(G) Drain(D) part. This will discharge the capacitor and provide power to the gate(G) at the same time 
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Blinking LED

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 This is a simple blinking led using a bc547 transistor. As it is in the diagram. You will need 1 transistor , 1 LED , Capacitor and a Resistor. This will work well on a 12v battery. Other types of batteries may not do the trick. The value of the capacitor will determine the blinking speeds.
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